For the equilibrium reaction:

2NOCl(g) ⇌ 2NO(g) + Cl₂(g)

The equilibrium constant in terms of concentration (Kc) is 3.0 × 10⁻⁶ at 1000 K.
Calculate the value of Kp for the reaction at this temperature.

 (Given R - 8.314 JK-1):
1. \(1.493\) 2. \(2.494\times10^{-2}\)
3. \(3.0\times10^{-6}\) 4. \(2.494\times10^{-4}\)
Subtopic:  Kp, Kc & Factors Affecting them |
 77%
Level 2: 60%+
NEET - 2024
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Consider the following reaction in a sealed vessel at equilibrium:
\(2 \text{NO}_{(\text{g})} \rightleftharpoons \text{N}_{2(\text{g})} +\text{O}_{2\text{(g)}}\)
[Given: \(\text{N}_2=3.0 \times 10^{-3} \text{M}, \text{O}_2=4.2 \times 10^{-3} \text{M}\) and \(\text{NO}=2.8 \times 10^{-3} \text M\)]

If 0.1 mol L-1 of NO(g) is taken in a closed vessel, what will be the degree of dissociation (\(\alpha\)) of NO(g) at equilibrium?
1. 0.0889
2. 0.00717
3. 0.717
4. 0.00889
Subtopic:  Introduction To Equilibrium |
Level 3: 35%-60%
NEET - 2024
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For the reaction \(2 \mathrm{A} \rightleftharpoons \mathrm{B}+\mathrm{C}; ~\mathrm{K}_{\mathrm{c}}=4 \times 10^{-3}\).
At a given time, the composition of the reaction mixture is : \([\mathrm{A}]=[\mathrm{B}]=[\mathrm{C}]=2 \times 10^{-3} \mathrm{M} \text {. }\)

In light of the above facts, which of the following is correct?
1. Reaction has a tendency to go in the forward direction.
2. Reaction has a tendency to go in the backward direction.
3. Reaction has gone to completion in the forward direction.
4. Reaction is at an equilibrium.
Subtopic:  Kp, Kc & Factors Affecting them | Le Chatelier's principle |
 58%
Level 3: 35%-60%
NEET - 2024
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Match the following equilibria with the corresponding condition.

A. Liquid ⇌ Vapour I. Saturated solution
B. Solid ⇌ Liquid II. Boiling point
C. Solid ⇌ Vapour III. Sublimation point
D. Solute (s) ⇌ Solute (solution) IV. Melting point
V Unsaturated solution

Codes:

A B C D
1. II IV III I
2. I II III V
3. V IV III II
4. IV V III II
Subtopic:  Introduction To Equilibrium |
 90%
Level 1: 80%+
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In the reaction, N2O4(g) ⇌ 2NO2(g), α is that part of N2O4 which dissociates. The number of moles at equilibrium will be:

1. 1-α2

2. 3α

3. α

4. 1+α

Subtopic:  Introduction To Equilibrium |
 75%
Level 2: 60%+
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I2(s) + 5F2(g)  →2IF5(g) 

The equilibrium constant Kc expression for the above mentioned reaction is:
1. \(\mathrm{K_{C} = \dfrac{\left[IF_{5}\right]^{2}}{\left[F_{2}\right]^{5}}}\) 2. \(\mathrm{K_{C} = \dfrac{\left[IF_{5}\right]^{2}}{\left[F_{2}\right]^{5} \left[I_{2}\right]}}\)
3. \(\mathrm{K_{C} = \dfrac{\left[F_{2}\right]^{5} \left[I_{2}\right]}{\left[IF_{2}\right]^{2}}}\) 4. \(\mathrm{K_{C} = \dfrac{\left[F_{2}\right]^{5}}{\left[IF_{5}\right]^{2}}}\)
Subtopic:  Introduction To Equilibrium |
 81%
Level 1: 80%+
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Ka1, Ka2 and Ka3 are the respective ionisation constants for the following reactions.
\(\mathrm{H}_2 \mathrm{~S} \rightleftharpoons \mathrm{H}^{+}+\mathrm{HS}^{-}\)
\(\mathrm{HS}^{-} \rightleftharpoons \mathrm{H}^{+}+\mathrm{S}^{2-}\)
\(\mathrm{H}_2 \mathrm{~S} \rightleftharpoons 2 \mathrm{H}^{+}+\mathrm{S}^{2-}\)
The correct relationship between Ka1, Ka2 and Ka3 is:
1. \(\mathrm{K}_{\mathrm{a}_3}=\mathrm{K}_{\mathrm{a}_1} \times \mathrm{K}_{\mathrm{a}_2} \)
2. \(\mathrm{K}_{\mathrm{a}_3}=\mathrm{K}_{\mathrm{a}_1}+\mathrm{K}_{\mathrm{a}_2} \)
3. \(K_{a_3}=K_{a_1}-K_{a_2} \)
4. \(\mathrm{K}_{\mathrm{a}_3}=\mathrm{K}_{\mathrm{a}_1} / \mathrm{K}_{\mathrm{a}_2}\)

Subtopic:  Introduction To Equilibrium |
 82%
Level 1: 80%+
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Reaction quotient for the reaction, N2(g)+3H2(g)⇌2NH3(g) is given by , Q = [NH3]2[N2][H2]3 .The reaction will proceed from right to left if Kc value is:

1. Q<Kc  2. Q=0
3. Q>Kc  4. Q=Kc 
Subtopic:  Introduction To Equilibrium |
 76%
Level 2: 60%+
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An incorrect statement about equilibrium among the following is:

1. Equilibrium is possible only in a closed system at a constant temperature.
2. All measurable properties of the system remain constant.
3. All the physical processes stop at equilibrium.
4. The opposing processes occur at the same rate and there is a dynamic but stable condition.
Subtopic:  Introduction To Equilibrium |
 75%
Level 2: 60%+
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For a reaction, 2NO (g) + Br2 (g)  ⇋2NOBr (g)

When 0.087 mol of NO and 0.0437 mol of Br2 are mixed in a closed container of volume 1 litre at a constant temperature, 0.0518 mol of NOBr is obtained at equilibrium. The concentration of NO and Br2 at equilibrium will be:

1. NO = 0.0352 mol; Br2= 0.0178 mol

2. NO = 0.352 mol; Br2= 0.178 mol

3. NO = 0.0634 mol; Br2= 0.0596 mol

4. NO = 0.634 mol; Br2= 0.596 mol

Subtopic:  Introduction To Equilibrium |
 73%
Level 2: 60%+
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