- 1(current)
Q. No.The velocity of a particle is \(v=v_0+g t+{Ft}^2.\) Its position is \(x = 0\) at \(t = 0,\) then its displacement after time \((t = 1)\) is:
1. \(v_0+\frac{g}{2}+\frac{F}{3}\)
2. \(v_0+\frac{g}{2}+F\)
3. \(v_0+2 g+3 F\)
4. \(v_0+g+F\)
1. \(v_0+\frac{g}{2}+\frac{F}{3}\)
2. \(v_0+\frac{g}{2}+F\)
3. \(v_0+2 g+3 F\)
4. \(v_0+g+F\)
Subtopic: Distance & Displacement |
Please attempt this question first.
Hints
Please attempt this question first.
A butterfly is flying with a velocity \(4\sqrt2~\text{m/s}\) in a North-East direction. The wind is slowly blowing at \(1~\text{m/s}\) from North to South. The resultant displacement of the butterfly in \(3\) seconds is:
1. \(15~\text{m}\)
2. \(20~\text{m}\)
3. \(3~\text{m}\)
4. \(12\sqrt2~\text{m}\)
1. \(15~\text{m}\)
2. \(20~\text{m}\)
3. \(3~\text{m}\)
4. \(12\sqrt2~\text{m}\)
Subtopic: Distance & Displacement |
Please attempt this question first.
Hints
Please attempt this question first.
A boy reaches the airport and finds that the escalator is not working. He walks up the stationary escalator in time \({t}_1 .\) If he remains stationary on a moving escalator then the escalator takes him up in time \({t}_2 .\) The time taken by him to walk up on the moving escalator will be:
1. \(\dfrac{t_1 t_2}{t_2+t_1}\)
2. \({t}_2\text-{t}_1\)
3. \(\dfrac{t_1+t_2}{2}\)
4. \(\dfrac{t_1 t_2}{t_2-t_1}\)
1. \(\dfrac{t_1 t_2}{t_2+t_1}\)
2. \({t}_2\text-{t}_1\)
3. \(\dfrac{t_1+t_2}{2}\)
4. \(\dfrac{t_1 t_2}{t_2-t_1}\)
Subtopic: Distance & Displacement |
Please attempt this question first.
Hints
Please attempt this question first.
Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at \(4^\text{th}\) second after its fall to the next droplet is \(34.3~\text{m.}\) At what rate the droplets are coming from the tap?
(Take \(g = 9.8~\text{m/s}^2\))
1. \(1\) drop /\(7\) seconds
2. \(3\) drops /\(2\) seconds
3. \(1\) drop / second
4. \(2\) drops / second
(Take \(g = 9.8~\text{m/s}^2\))
1. \(1\) drop /\(7\) seconds
2. \(3\) drops /\(2\) seconds
3. \(1\) drop / second
4. \(2\) drops / second
Subtopic: Distance & Displacement |
Please attempt this question first.
Hints
Please attempt this question first.
A balloon was moving upwards with a uniform velocity of \(10~\text{m/s.}\) An object of finite mass is dropped from the balloon when it was at a height of \(75 ~\text{m}\) from the ground level. The height of the balloon from the ground when the object strikes the ground will be:
(takes the value of \(g\) as \(\mathrm{10 m /s^2}\))
1. \(250~\text{m}\)
2. \(300~\text{m}\)
3. \(200~\text{m}\)
4. \(125~\text{m}\)
(takes the value of \(g\) as \(\mathrm{10 m /s^2}\))
1. \(250~\text{m}\)
2. \(300~\text{m}\)
3. \(200~\text{m}\)
4. \(125~\text{m}\)
Subtopic: Distance & Displacement |
Please attempt this question first.
Hints
Please attempt this question first.
Water drops are falling from the nozzle of a shower onto the floor, from a height of \(9.8~\text{m.}\) The drops fall at regular intervals of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Then the position of the second drop from the floor when the first drop strikes the floor is:
1. \(4.18~ \text{m}\)
2. \(2.94~ \text{m}\)
3. \(2.45~ \text{m}\)
4. \(7.35~ \text{m}\)
1. \(4.18~ \text{m}\)
2. \(2.94~ \text{m}\)
3. \(2.45~ \text{m}\)
4. \(7.35~ \text{m}\)
Subtopic: Distance & Displacement |
Please attempt this question first.
Hints
Please attempt this question first.
The velocity–time \((v \text-t)\) graph of a body moving along a straight line is shown in the figure.
The ratio of displacement to distance travelled by the body in time \(0~\text s\) to \(10~\text s\) is:
1. \(1 : 1\)
2. \(1 : 4\)
3. \(1 : 3\)
4. \(1 : 2\)
The ratio of displacement to distance travelled by the body in time \(0~\text s\) to \(10~\text s\) is:
1. \(1 : 1\)
2. \(1 : 4\)
3. \(1 : 3\)
4. \(1 : 2\)
Subtopic: Distance & Displacement |
69%
Level 2: 60%+
Please attempt this question first.
Hints
Please attempt this question first.
A particle has uniform acceleration. If its displacement from \(t\) to \(t+1\) second is \(120~\text m\) and the change in velocity is \(50 ~\text{m/s}.\) Then its displacement in \(t+2\) second is:
1. \(100~\text m\)
2. \(120~\text m\)
3. \(140~\text m\)
4. \(170~\text m\)
1. \(100~\text m\)
2. \(120~\text m\)
3. \(140~\text m\)
4. \(170~\text m\)
Subtopic: Distance & Displacement |
Please attempt this question first.
Hints
Please attempt this question first.
- 1(current)
Q. No.
© 2026 GoodEd Technologies Pvt. Ltd.