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Q. No.| Statement I: | Work done by electrostatic force is zero if a charge is moving along an equipotential surface. |
| Statement II: | Equipotential surfaces are perpendicular to the electric field. |
| 1. | Statement I is correct and Statement II is incorrect. |
| 2. | Statement I is incorrect and Statement II is correct. |
| 3. | Both Statement I and Statement II are incorrect. |
| 4. | Both Statement I and Statement II are correct. |
Subtopic: Equipotential Surfaces |
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Level 1: 80%+
JEE
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Three infinitely long wires with linear charge density \(λ\) are placed along the \(x-\)axis, \(y-\)axis and \(z-\)axis respectively. Which of the following denotes an equipotential surface?
| 1. | 1. \(xyz\) constant |
| 2. | \((x+y)(y+z)(z+x)= \) constant |
| 3. | \(x y+y z+z x= \) constant |
| 4. | \(\left(x^2+y^2\right)\left(y^2+z^2\right)\left(z^2+x^2\right)= \) constant |
Subtopic: Equipotential Surfaces |
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