The output of a step-down transformer is measured to be \(24\) V when connected to a \(12\) W light bulb. The value of the peak current is:

1. \(\dfrac{1}{\sqrt{2}}~\text{A}\) 2. \(\sqrt{2}~\text{A}\)
3. \(2~\text{A}\) 4. \(2\sqrt{2}~\text{A}\)