Ncert Exercises & Solutions

The gravitational force between \(\text H\text-\)atom and another particle of mass \(m\) will be given by Newton's law \(F=\dfrac{GMm}{r^2},\) where \(r\) is in \(\text{km}\) and;

1.	\(M = m_{\text{proton}}+ m_{\text{electron}}.\)
2.	\(M = m_{\text{proton}}+ m_{\text{electron}}-\frac{B}{c^2}\left(B= 13.6~\text{eV}\right)\).
3.	\(M\) is not related to the mass of the hydrogen atom.
4.	\(M = m_{\text{proton}}+ m_{\text{electron}}-\frac{\|V\|}{c^2}(\|V\|=\) magnitude of the potential energy of electron in the \(\text H\text-\)atom).

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