Nuclei with magic number of proton Z = 2, 8, 20, 28, 50, 52 and magic number of neutrons N = 2, 8, 20, 28, 50, 82 and 126 are found to be very stable.

(i) Verify this by calculating the proton separation energy Sp for 120Sn (Z=50) and 121Sb (Z=51).

The proton separation energy for a nuclide is the minimum energy required to separate the least tightly bound proton from a nucleus of that nuclide. It is given by:

Sp=(Mz-1,N+MH-MZ,N)c2.

Given,

119ln=118.9058u,120Sn=199.902199u,
121Sb=120.903824u,1H=1.0078252u.

(ii) What does the existence of magic number indicate?