Ncert Exercises & Solutions

The van't Hoff factor (i) is given by the expression:

(a) $i = \frac{Normal molar mass}{Abnormal molar mass}$

(b) $i = \frac{Abnormal molar mass}{Normal molar mass}$

(c) $i = \frac{Observed colligative property}{Calculated colligative property}$

(d) $i = \frac{Calculated colligative property}{Observed colligative property}$

The correct choice among the given options is:

1.	a and b	2.	b and c
3.	c and d	4.	a and c

Hint: Van't Hoff factor

(i) = \frac{normal molar mass}{abnormal molar mass}

Van’t Hoff factor (i) accounts for association or dissociation of solute in solution.

When a solute dissociates, the observed molar mass becomes smaller than the normal molar mass.
Hence, $ i = \frac{\text{Normal molar mass}}{\text{Abnormal molar mass}}$ , (a) is correct.

Colligative properties depend on number of particles. Due to dissociation/association, the observed value differs from the calculated (ideal) value
Therefore, $ i = \frac{\text{Observed colligative property}}{\text{Calculated colligative property}}$ (c) is correct.

Options (b) and (d) are incorrect because they represent the inverse of the correct expressions

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